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我想問下....係 Cl2→PCl5果度....點解P既O.N. 係0→ -1 既..點樣 計-1 0我知..唔識計個-1出黎..唔該教教
最佳解答:
Since P can have variable oxidation states, due to using expanded d-orbital to form bonds, you can't calculate it directly. The best way to find out its (P) oxidation state is as follows: P + (-1)x5 = 0(zero) . The oxidation state of P is P +(-5) = 0 . P = 5 Having found out the oxidation state of P, you can found the oxidation state of Cl easily: 5 + (Cl)x5 = 0 ===> 5 Cl = -5 ===> Cl = 5/-5 = -1. Hence Cl2 (0) --> PCl5 (-1) I hope you may find my answer helpful.
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氧化數問題................發問:
我想問下....係 Cl2→PCl5果度....點解P既O.N. 係0→ -1 既..點樣 計-1 0我知..唔識計個-1出黎..唔該教教
最佳解答:
Since P can have variable oxidation states, due to using expanded d-orbital to form bonds, you can't calculate it directly. The best way to find out its (P) oxidation state is as follows: P + (-1)x5 = 0(zero) . The oxidation state of P is P +(-5) = 0 . P = 5 Having found out the oxidation state of P, you can found the oxidation state of Cl easily: 5 + (Cl)x5 = 0 ===> 5 Cl = -5 ===> Cl = 5/-5 = -1. Hence Cl2 (0) --> PCl5 (-1) I hope you may find my answer helpful.
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