入
close
標題:
A concept do not understand
發問:
最佳解答:
Usually x and y are variables and a, h and k are constant. In your case, y varies according to x^2, Therefore, the formula could be plotted as a parabola with open downwards. There is an instant that x = h Then y = a(0)^2 + k = k which is a special point of this parabola (h, k) which is the highest point of the parabola.
其他解答:
A concept do not understand
發問:
此文章來自奇摩知識+如有不便請留言告知
Explain it! y = a(x - h)^2 + k Is x = h? If Yes, Assume h is 6, x is also 6. Then a(6-6)^2, this things would be 0.最佳解答:
Usually x and y are variables and a, h and k are constant. In your case, y varies according to x^2, Therefore, the formula could be plotted as a parabola with open downwards. There is an instant that x = h Then y = a(0)^2 + k = k which is a special point of this parabola (h, k) which is the highest point of the parabola.
其他解答:
文章標籤
全站熱搜
留言列表
