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因式分解 !~~~~!!!jk

發問:

因式分解 3x^3-6x^2+x-2

最佳解答:

3x^3-6x^2+x-2 =3x^2(x-2)+x-2 =(x-2)(3x^2+1)

其他解答:

3x^3-6x^2+x-2 =3x^2(x-2) + x-2 = (x-2)(3x^2+1) or f(x) = 3x^3-6x^2+x-2 f(1) = 3(1)^3-6(1)^2+1-2 = 3 -6 -1 = -4 f(2) = 3(2)^3-6(2)^2+2-2 = 3(8) - 24 = 0 根據因式定理, (x-2)是f(x)的其中一個因式 3x^2 +1 --------------------- x-2 ) 3x^3-6x^2+x-2 3x^3-6x^2 --------------------- x-2 x-2 --------------------- 所以 3x^3-6x^2+x-2= (x-2)(3x^2+1) 2009-01-08 20:48:40 補充: 3x^2 +1 -------------------- x-2 )3x^3-6x^2+x-2 3x^3-6x^2 ------------------- x-2 x-2 ------------------- 2009-01-08 20:50:36 補充: . 3x^2 +1 . -------------------- x-2 )3x^3-6x^2+x-2 . 3x^3-6x^2 . ------------------- . x-2 . x-2 . ------------------- 2009-01-08 20:51:58 補充: ...................3x^2 +1 ...... -------------------- x-2 )3x^3-6x^2+x-2 ...... 3x^3-6x^2 ....... ------------------- ......................... x-2 ......................... x-2 ....... ------------------- 2009-01-08 20:53:52 補充: 2009-01-08 20:50:33 補充 2009-01-08 20:52:29 補充 e2個可以唔洗理
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